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6n^2-2n=330
We move all terms to the left:
6n^2-2n-(330)=0
a = 6; b = -2; c = -330;
Δ = b2-4ac
Δ = -22-4·6·(-330)
Δ = 7924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7924}=\sqrt{4*1981}=\sqrt{4}*\sqrt{1981}=2\sqrt{1981}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{1981}}{2*6}=\frac{2-2\sqrt{1981}}{12} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{1981}}{2*6}=\frac{2+2\sqrt{1981}}{12} $
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